数独 发表于 2016-10-13 | 分类于 C/C++ | | | 数独求解 12345678910111213141516171819202122232425262728293031323334353637383940414243444546474849505152535455565758596061626364656667686970717273747576777879808182838485868788899091929394959697#include <stdio.h>#define UNASSIGNED 0#define N 9 // NxN 的大小// 是否还有未放置的位置int FindUnassignedLocation(int grid[N][N], int *row, int *col);// 在位置 grid[row][col]处,是否可以放置numint isSafe(int grid[N][N], int row, int col, int num);int SolveSudoku(int grid[N][N]) // 回溯法求解{ int row, col; int *p1,*p2; p1=&row; p2=&col; if (FindUnassignedLocation(grid, p1, p2)==0)//都已经放置完,则返true return 1; // success! for (int num = 1; num <= 9; num++) { if (isSafe(grid, row, col, num)) { grid[row][col] = num; // 放置棋子 if (SolveSudoku(grid)) // return, if success, yay! return 1; grid[row][col] = UNASSIGNED; // 失败, 设置为 未放置的 & 再一次尝试 } } return 0;}int FindUnassignedLocation(int grid[N][N], int *row, int *col){ for (*row = 0; *row < N; (*row)++) for (*col = 0; *col < N; (*col)++) if (grid[*row][*col] == UNASSIGNED) return 1; return 0;}int UsedInRow(int grid[N][N], int row, int num){ for (int col = 0; col < N; col++) if (grid[row][col] == num) return 1; return 0;}int UsedInCol(int grid[N][N], int col, int num){ for (int row = 0; row < N; row++) if (grid[row][col] == num) return 1; return 0;}int UsedInBox(int grid[N][N], int boxStartRow, int boxStartCol, int num){ for (int row = 0; row < 3; row++) for (int col = 0; col < 3; col++) if (grid[row+boxStartRow][col+boxStartCol] == num) return 1; return 0;}int isSafe(int grid[N][N], int row, int col, int num){ return UsedInRow(grid, row, num)==0 &&UsedInCol(grid, col, num)==0 &&UsedInBox(grid, row - row%3 , col - col%3, num)==0;}void printGrid(int grid[N][N]){ for (int row = 0; row < N; row++) { for (int col = 0; col < N; col++) printf("%4d", grid[row][col]); printf("\n\n"); }}/* 测试 */int main(){ int grid[N][N] = {{3, 0, 6, 5, 0, 8, 4, 0, 0}, {5, 2, 0, 0, 0, 0, 0, 0, 0}, {0, 8, 7, 0, 0, 0, 0, 3, 1}, {0, 0, 3, 0, 1, 0, 0, 8, 0}, {9, 0, 0, 8, 6, 3, 0, 0, 5}, {0, 5, 0, 0, 9, 0, 6, 0, 0}, {1, 3, 0, 0, 0, 0, 2, 5, 0}, {0, 0, 0, 0, 0, 0, 0, 7, 4}, {0, 0, 5, 2, 0, 6, 3, 0, 0}}; if (SolveSudoku(grid)) printGrid(grid); else printf("No solution exists"); return 0;} 运行结果截图: